$\left(a^2-2ab+b^2\right)^2$

$\frac{x^2}{z^3}^4$

$f\left(x\right)=\frac{\left(6x^5\right)}{8-4x^3}$

$\frac{dy}{dx}\left(\frac{xy^2-\cos\left(x\right)sen\left(x\right)}{y\left(1-x^2\right)}\right)$

$9x^2+18x$

$\left(-19+21\right)-2+\left(32-43\right)-3$

$-\frac{4}{3}+x=\frac{2}{3}$