$8x^6-27$
$4x+8=2x-12$
$3x-2y+5y-4x-3x+y$
$16x^2-32x-16$
$\sin\left(3x\right)=2\sin^2\left(3x\right)$
$\lim_{x\to\infty}\left(\frac{ln\left(1+2x^3\right)}{4+ln\:x}\right)$
$\frac{3x^2}{-x}$
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