$dy=\left(10x+7\right)dx$
$3\sqrt{x}+38=41$
$\lim_{x\to\infty}\left(\frac{2\left(\left(x^2-1\right)e^{\frac{1}{x^2}}-x^2\right)}{x}\right)$
$\sqrt[5]{64v^{7}}$
$37^3-26^3+76$
$-12x-8x-7x-2x$
$25+\frac{7\left(12-2^2\right)}{4}$
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