$x^{-0.5}$
$x^3+y^3=6x$
$\left(10x^2+6x\right)-\left(4x^2-3\right)$
$\frac{13-12i}{4+5i}\:\cdot\:\frac{4-5i}{4-5i}$
$\log_{12}3+\log_{12}48$
$2^3.5^3$
$7+3\cdot8-3\cdot7+12$
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