$\int\frac{\ln\left(y\right)}{3y^3}dy$
$\frac{3}{x+2}=\frac{x-3}{2x+4}$
$\int\frac{5}{\left(t+10\right)^6}dt$
$4\left(x+2\right)-3\left(x-5\right)v$
$14x^2+8x^3-4x^3-2x^2-3x^2-8x^4$
$25x^{2}-49y^{4}$
$\frac{dy}{dx}=y=x^5$
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