$\int\frac{1}{\sin2020x}dx$
$\left(x^2-x+2\right)^2$
$\frac{1}{x}-\frac{x}{x\left(x^2+4\right)}$
$\left(\frac{2}{3}x-4y^2\right)^2$
$x\cos\left(y\right)\frac{dy}{dx}=2x-seny$
$\frac{dy}{dx}=\frac{3+16x}{xy^2}$
$sczs$
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