$\left(4x-5\right)\cdot\left(3x^2\right)$
$\cot\:\left(-x\right)\cos\:\left(-x\right)+\sin\:\left(-x\right)$
$16x^2\:y^2-z^4$
$\cos\left(b-a\right)=\cos\left(b\right)\cos\left(a\right)+\sin\left(b\right)\sin\left(a\right)$
$3cot^2x-1=0$
$y^2-y=x^2-x$
$-347-189$
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