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$\frac{\left(3x+3\right)}{a}\ge\:5x+5$

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Other solved exercises

$2\left(x+5\right)-7$

$\frac{2x-6}{4}=5$

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$\frac{729-512b^{3}}{9-8b}$

$x'-0.5x=t^2$

$18+9+9x-3+5x$

$2x+15=-7$
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