$-0.75x^3+9x-15$

$1-\frac{\cos2\left(x\right)}{1-\sin\left(x\right)}=-\sin\left(x\right)$

$\:\int\:\frac{4x+6}{x^3+x^2-2x}dx$

$0.5-1.5$

$\int\frac{4x^2+4x-35}{x^2-9}dx$

$-\left(-3\right)+\left(-44\right)$

$\sec x-\cos\left(x\right)=\sin\left(x\right)\tan\left(x\right)$