$\int_2^{\infty}\left(\frac{1}{\left(\sqrt{1+x^2}\right)}\right)dx$
$\left(\frac{1}{6}-y\right)^2$
$\frac{\left(1+x\right)^6}{x^3}$
$\sqrt{89x^2}$
$\int\left(\frac{3x^2}{1-x^3}\right)dx$
$2x^3-5x^2-23x-10$
$\frac{dy}{dx}=\frac{4+11x}{xy^2}$
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