$\lim_{x\to0}\left(\frac{e^{\sqrt{x}}}{x}\right)$
$\left(-1\left(9\right)\left(-9\right)\right)$
$x^2+12>8x$
$9k^2-25$
$\frac{3-9}{4-6}$
$x\ge6-x$
$32.354-1.05$
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