$x=2-y^2$
$\lim_{x\to\infty}\left(\frac{e^x+4x}{x-e^x}\right)$
$\frac{4}{5}y\:\frac{24}{30}$
$\left(2x^4-6x^3-4x^2+17x-15\right)\left(x-3\right)$
$4c^2+12cd+9d^2$
$\left|26-24\right|^5-2^4$
$\left(\:-\:42\:\right)\::\:\left(\:-\:7\:\right)\:$
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