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Exercise

$\lim_{x\to\frac{\pi}{2}}\left(\frac{sin\left(x\right)\sqrt{sin^2x+9cos^2t}}{2cosx}\right)$

Final answer to the exercise

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Other solved exercises

$\frac{dp}{dq}=\frac{p}{q^{-1}}$

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$-47^2$

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$535-223$
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