$x^2-4x+5>0$
$\frac{d}{dx}\left(\frac{sin^2x+tan^4x}{\left(x^2+2\right)^2}\right)$
$\int\left(\frac{12}{\left(4x-9\right)^4}\right)dx$
$\int_5^0\left(\sqrt{25-x^2}\right)dx$
$57^2$
$\frac{x}{5}-2<6$
$-10\left(1-9x\right)+6\left(x+10\right)$
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