$\lim_{x\to2}\left(4^x-16\right)^{4-x^2}$
$\frac{dy}{dx}=secx$
$5y^3\:+\:2y^3\:+\:4y^3\:+\:4y^3\:-\:6y^3\:+\:5x^{3\:}-\:3\:-\:3$
$\lim_{x\to1.1}\left(\frac{x-2}{x^2+x-6}\right)$
$f\left(50\right)=-2.1\left(50\right)+247$
$-\frac{1}{4y+6}$
$x^3+5x^2-29x-105$
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