$\frac{\sin^2\left(x\right)+\sin\left(x\right)\cos\left(x\right)}{1+\frac{1}{\tan\left(x\right)}}=\sin^2\left(x\right)$

$-100-6500$

$-8\:-\:\left(-50\right)$

$-\left(+28-30\right)-\left(10+23\right)$

$\tan^22x=\frac{3}{4}$

$9y^2+72y$

$\int_1^{\infty}\left(\frac{1}{\left(x+2\right)\left(x+4\right)}\right)dx$