$2+2x^2-4$

$\left(\frac{1}{3}x^2+5\right)^3$

$\lim_{x\to\frac{\pi}{4}}\left(\frac{7tan\left(x\right)-7cot\left(x\right)}{4x-\pi}\right)$

$\frac{n^6+1^3}{n+1}$

$\lim_{x\to0}\left(\frac{9x\left(cos\left(2x\right)\right)-1}{sin\left(9x\right)-9x}\right)$

$3t-153\le-159$

$\frac{1+sec^2}{1+tan^2}$