$\frac{\left(-2m^4\right)^2}{8m^2}$
$4x+3+7x$
$x+5=8$
$\left(-2.5\right)^2\cdot\left(-3.4\right)^3$
$\frac{x-2}{x^2-4x+4}+1$
$\lim_{x\to\infty}\left(\frac{\tan\left(x\right)}{\tan\left(4x\right)}\right)$
$\frac{3x^2-5x+1}{\left(x-2\right)\left(x^2+4x+5\right)}$
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