$\left(\sqrt{x}-y^2\right)\left(\sqrt{x}+y^2\right)$

$\int\left(\frac{-1}{\sqrt{5t+1}}\right)dt$

$\frac{d}{dx}\left(arc\:\sec\left(x^2+2x+1\right)\right)$

$36a^4-6a^2b+\frac{b^2}{4}$

$\int\frac{5x}{\left(x+2\right)\left(x^2+1\right)}dx$

$\sqrt{2x-5=5}$

$x^5\:-\:2x^4\:-\:2x^3\:+\:5\::\:2x^3\:-\:2x^2\:+\:x\:-\:1$