$\frac{dx}{dy}=tan\left(y\right)$
$3\csc\left(x\right)=2\sqrt{3}$
$\frac{dy}{dx}=\frac{2x^4}{3y^2}$
$\frac{x^3+x^2-6x}{x^2}$
$-7y-2-4x-2x+6x+6y-2$
$x\frac{dy}{dx}+y=x^2y^3$
$\lim_{x\to\infty}\frac{1-2x}{x+1}$
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