$f\left(x\right)=\frac{8}{3}\left(x^2-x\right)^3$
$x+2=3x-2$
$a=\left(2x-3\right)^2-\left(2x+3\right)^2+\left(3x+4\right)^2-8x^2-16$
$2a-a^2$
$16m^2-40m+25$
$5m+m^2-1$
$\frac{t}{t+1}-\frac{2}{t+3}=\frac{8}{t^2+2t-3}$
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