$4^3+5\cdot4-1$
$x3-9x$
$5x-7^2$
$\left(a^{x-2}+5\right)^2$
$\frac{\frac{x}{y}}{a}$
$\sqrt[6]{x+3}=\sqrt[3]{2x+1}$
$-5\cdot\left(9-\frac{8}{4}+1\right)-215:5$
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