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Solve the equation $\frac{12x+10y}{2}=30$

Step-by-step Solution

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Final answer to the problem

$y=\frac{6\left(5-x\right)}{5}$
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Step-by-step Solution

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  • Solve for x
  • Solve for y
  • Find the derivative
  • Solve by implicit differentiation
  • Solve for y'
  • Find dy/dx
  • Derivative
  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
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Factor the polynomial $12x+10y$ by it's greatest common factor (GCF): $2$

$\frac{2\left(6x+5y\right)}{2}=30$

Learn how to solve two-variable linear equations problems step by step online.

$\frac{2\left(6x+5y\right)}{2}=30$

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Learn how to solve two-variable linear equations problems step by step online. Solve the equation (12x+10y)/2=30. Factor the polynomial 12x+10y by it's greatest common factor (GCF): 2. Take \frac{2}{2} out of the fraction. We need to isolate the dependent variable y, we can do that by simultaneously subtracting 6x from both sides of the equation. Factor the polynomial 30-6x by it's greatest common factor (GCF): 6.

Final answer to the problem

$y=\frac{6\left(5-x\right)}{5}$

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Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

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Function Plot

Plotting: $\frac{12x+10y}{2}-30$

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Answer Assistant

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Got a different answer? Verify it!

Go!
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2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Two-variable linear equations

Algebraic equations that have two distinct variables.

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