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\frac{d}{dx}\left(\ln\left(\sqrt{x^2+2x}\right)\right)

Find the derivative of ln((x^2+2x)^0.5)

Answer

$\frac{1+x}{2x+x^2}$

Step-by-step explanation

Problem

$\frac{d}{dx}\left(\ln\left(\sqrt{x^2+2x}\right)\right)$
1

The derivative of the natural logarithm of a function is equal to the derivative of the function divided by that function. If $f(x)=ln\:a$ (where $a$ is a function of $x$), then $\displaystyle f'(x)=\frac{a'}{a}$

$\frac{1}{\sqrt{2x+x^2}}\cdot\frac{d}{dx}\left(\sqrt{2x+x^2}\right)$

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Answer

$\frac{1+x}{2x+x^2}$

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$\frac{d}{dx}\left(\ln\left(\sqrt{x^2+2x}\right)\right)$

Main topic:

Differential calculus

Used formulas:

3. See formulas

Time to solve it:

~ 0.4 seconds