$\frac{1}{x}:\frac{3x^2}{4}=\frac{4}{3x^3}$
$44.94=6x+1x$
$4sin^2+3$
$-403\:-\:-177$
$3x^3+x^2-38x+24$
$\left(-19\right)\left(-7\right)$
$\lim_{x\to+3}\left(\frac{3x^2+1}{x+3}\right)$
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