Final Answer
Step-by-step Solution
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Rewrite the expression $\frac{6x^2+22x-23}{\left(2x-1\right)\left(x^2+x-6\right)}$ inside the integral in factored form
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$\int\frac{6x^2+22x-23}{\left(2x-1\right)\left(x-2\right)\left(x+3\right)}dx$
Learn how to solve problems step by step online. Find the integral int((6x^2+22x+-23)/((2x-1)(x^2+x+-6)))dx. Rewrite the expression \frac{6x^2+22x-23}{\left(2x-1\right)\left(x^2+x-6\right)} inside the integral in factored form. Rewrite the fraction \frac{6x^2+22x-23}{\left(2x-1\right)\left(x-2\right)\left(x+3\right)} in 3 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by \left(2x-1\right)\left(x-2\right)\left(x+3\right). Multiplying polynomials.