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Find the limit $\lim_{x\to{\frac{29}{10}}}\left(\frac{x^2-8x+15}{x-3}\right)$

Step-by-step Solution

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Solution

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Final Answer

$-\frac{21}{10}$
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Step-by-step Solution

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$\lim_{x\to\frac{29}{10}}\left(\frac{x^2-8x+15}{x-3}\right)$

Learn how to solve limits by direct substitution problems step by step online.

$\lim_{x\to\frac{29}{10}}\left(\frac{x^2-8x+15}{x-3}\right)$

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Learn how to solve limits by direct substitution problems step by step online. Find the limit (x)->(29/10)lim((x^2-8x+15)/(x-3)). Simplifying. Evaluate the limit \lim_{x\to\frac{29}{10}}\left(\frac{x^2-8x+15}{x-3}\right) by replacing all occurrences of x by 2.9. Subtract the values \frac{29}{10} and -3. Multiply -8 times \frac{29}{10}.

Final Answer

$-\frac{21}{10}$

Exact Numeric Answer

$-2.1$

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Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Limits by Direct SubstitutionLimits by L'Hôpital's ruleLimits by FactoringLimits by Rationalizing

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Function Plot

Plotting: $\frac{x^2-8x+15}{x-3}$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Limits by Direct Substitution

Find limits of functions at a specific point by directly plugging the value into the function.

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