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A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: $(a-b)^2=a^2-2ab+b^2$
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$3\left(x+2\right)^2\left(x^2-6x+9\right)-2\left(x+2\right)^3\left(x-3\right)$
Learn how to solve special products problems step by step online. Expand the expression 3(x+2)^2(x-3)^2-2(x+2)^3(x-3). A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. Expand \left(x+2\right)^2. Multiply the single term 3\left(x^2-6x+9\right) by each term of the polynomial \left(x^2+4x+4\right). Multiply the single term 3x^2 by each term of the polynomial \left(x^2-6x+9\right).