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$3x^2-2x-2x^2\geq 15$
Learn how to solve differential calculus problems step by step online. Solve the inequality 3x^2-2x>=2x^2+15. Grouping terms. Combining like terms 3x^2 and -2x^2. Factor the polynomial x^2-2x. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value -2. Now, we can factor x^2+-2x+1 as a squared binomial of the form \left(x+\frac{b}{2}\right)^2.