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Solve the inequality $9x-3\left(3x-7u\right)>7i$

Step-by-step Solution

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Solution

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Final Answer

$u>\frac{1}{3}i$
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Step-by-step Solution

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Multiply the single term $-3$ by each term of the polynomial $\left(3x-7u\right)$

$9x-9x+21u>7i$

Learn how to solve integrals with radicals problems step by step online.

$9x-9x+21u>7i$

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Learn how to solve integrals with radicals problems step by step online. Solve the inequality 9x-3(3x-7u)>7i. Multiply the single term -3 by each term of the polynomial \left(3x-7u\right). Cancel like terms 9x and -9x. Divide both sides of the inequation by 21. Take \frac{7}{21} out of the fraction.

Final Answer

$u>\frac{1}{3}i$

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Function Plot

Plotting: $u>\frac{1}{3}i$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Integrals with Radicals

Integrals with radicals are those integrals that contain a radical (square root, cubic, etc.) in the numerator or denominator of the integral.

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