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Rewrite the expression $\frac{6}{x^2-5x+4}$ inside the integral in factored form
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$\int_{0}^{3}\frac{6}{\left(x-1\right)\left(x-4\right)}dx$
Learn how to solve definite integrals problems step by step online. Integrate the function 6/(x^2-5x+4) from 0 to 3. Rewrite the expression \frac{6}{x^2-5x+4} inside the integral in factored form. Rewrite the fraction \frac{6}{\left(x-1\right)\left(x-4\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B. The first step is to multiply both sides of the equation from the previous step by \left(x-1\right)\left(x-4\right). Multiplying polynomials.