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Integrate the function $\left(t+3\right)\cos\left(\frac{\pi n}{3}t\right)$ from $-3$ to 0

Step-by-step Solution

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Final Answer

$\frac{0.91189-0.91189\cos\left(\pi n\right)}{n^2}$
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Step-by-step Solution

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Take $\frac{\pi }{3}$ out of the fraction

$\int_{-3}^{0}\left(t+3\right)\cos\left(\frac{\pi}{3}nt\right)dt$

Learn how to solve definite integrals problems step by step online.

$\int_{-3}^{0}\left(t+3\right)\cos\left(\frac{\pi}{3}nt\right)dt$

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Learn how to solve definite integrals problems step by step online. Integrate the function (t+3)cos((npi)/3t) from -3 to 0. Take \frac{\pi }{3} out of the fraction. We can solve the integral \int\left(t+3\right)\cos\left(\frac{\pi}{3}nt\right)dt by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. First, identify u and calculate du. Now, identify dv and calculate v.

Final Answer

$\frac{0.91189-0.91189\cos\left(\pi n\right)}{n^2}$

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Function Plot

Plotting: $\left(t+3\right)\cos\left(\frac{\pi n}{3}t\right)$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

Used Formulas

7. See formulas

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