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Solve the inequality (20x*-1-16+5x^3+x^4)/(-13x+10+2x^2+x^3)#0

\frac{x^4+5x^3-1\cdot 20\cdot x-16}{x^3+2x^2-13\cdot x+10}\leq 0

Step by step solution

Problem

$\frac{x^4+5x^3-1\cdot 20\cdot x-16}{x^3+2x^2-13\cdot x+10}\leq 0$

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Answer

$\frac{\left(1+x\right)\left(4+x\right)\left(x^2-4\right)}{\left(x-1\right)\left(x-2\right)\left(5+x\right)}\leq 0$

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Problem Stats

Main topic:

Factor by difference of squares

Used formulas:

0

Time to solve it:

0.5 seconds

Views:

119