# Step-by-step Solution

## Integrate (x^2-4)^0.5

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### Videos

$4\left(\frac{\frac{1}{2}\left(\frac{x}{2}\right)^{2}\sqrt{x^2-4}}{x}+\frac{1}{2}\ln\left|\frac{x+\sqrt{x^2-4}}{2}\right|\right)-4\ln\left|\frac{x+\sqrt{x^2-4}}{2}\right|+C_0$

## Step-by-step explanation

Problem to solve:

$\int_{ }^{ }\left(\sqrt{\left(x^2-4\right)}\right)dx$
1

Solve the integral $\int\sqrt{x^2-4}dx$ by trigonometric substitution using the substitution

$\begin{matrix}x=2\sec\left(\theta\right) \\ dx=2\sec\left(\theta\right)\tan\left(\theta\right)d\theta\end{matrix}$
2

Substituting in the original integral, we get

$\int2\sqrt{4\sec\left(\theta\right)^2-4}\sec\left(\theta\right)\tan\left(\theta\right)d\theta$

$4\left(\frac{\frac{1}{2}\left(\frac{x}{2}\right)^{2}\sqrt{x^2-4}}{x}+\frac{1}{2}\ln\left|\frac{x+\sqrt{x^2-4}}{2}\right|\right)-4\ln\left|\frac{x+\sqrt{x^2-4}}{2}\right|+C_0$

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$\int_{ }^{ }\left(\sqrt{\left(x^2-4\right)}\right)dx$

### Main topic:

Integration by trigonometric substitution

~ 0.69 seconds