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Moving the term $-3$ to the other side of the inequation with opposite sign
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$x^2-5x<0+3$
Learn how to solve differential calculus problems step by step online. Solve the inequality x^2-5x+-3<0. Moving the term -3 to the other side of the inequation with opposite sign. Add the values 0 and 3. Factor the polynomial x^2-5x. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value -5. Now, we can factor x^2+-5x+\frac{25}{4} as a squared binomial of the form \left(x+\frac{b}{2}\right)^2.