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Factor the trinomial $y^2-12y+32$ finding two numbers that multiply to form $32$ and added form $-12$
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$\begin{matrix}\left(-4\right)\left(-8\right)=32\\ \left(-4\right)+\left(-8\right)=-12\end{matrix}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation y^2-12y+32=0. Factor the trinomial y^2-12y+32 finding two numbers that multiply to form 32 and added form -12. Thus. Break the equation in 2 factors and set each equal to zero, to obtain. Solve the equation (1).