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Expand the integral $\int_{1}^{9}\left(2x-3\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int_{1}^{9}2xdx+\int_{1}^{9}-3dx$
Learn how to solve definite integrals problems step by step online. Integrate the function 2x-3 from 1 to 9. Expand the integral \int_{1}^{9}\left(2x-3\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{1}^{9}2xdx results in: 80. The integral \int_{1}^{9}-3dx results in: -24. Gather the results of all integrals.