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Expand the integral $\int_{-2}^{-1}\left(2x^3+4x^2-2x-4\right)dx$ into $4$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int_{-2}^{-1}2x^3dx+\int_{-2}^{-1}4x^2dx+\int_{-2}^{-1}-2xdx+\int_{-2}^{-1}-4dx$
Learn how to solve definite integrals problems step by step online. Integrate the function 2x^3+4x^2-2x+-4 from -2 to -1. Expand the integral \int_{-2}^{-1}\left(2x^3+4x^2-2x-4\right)dx into 4 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{-2}^{-1}2x^3dx results in: -\frac{15}{2}. The integral \int_{-2}^{-1}4x^2dx results in: \frac{28}{3}. The integral \int_{-2}^{-1}-2xdx results in: 3.