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Expand the expression $\left(4x-3\right)^3$

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Final Answer

$64x^3-9\cdot 16x^2+108x-27$
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Step-by-step Solution

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The cube of a binomial (difference) is equal to the cube of the first term, minus three times the square of the first by the second, plus three times the first by the square of the second, minus the cube of the second term. In other words: $(a-b)^3=a^3-3a^2b+3ab^2-b^3 = (4x)^3+3(4x)^2(-3)+3(4x)(-3)^2+(-3)^3 =$

$\left(4x\right)^3+3\cdot -3\left(4x\right)^2+3\cdot 4\cdot {\left(-3\right)}^2x+{\left(-3\right)}^3$

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$\left(4x\right)^3+3\cdot -3\left(4x\right)^2+3\cdot 4\cdot {\left(-3\right)}^2x+{\left(-3\right)}^3$

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Learn how to solve special products problems step by step online. Expand the expression (4x-3)^3. The cube of a binomial (difference) is equal to the cube of the first term, minus three times the square of the first by the second, plus three times the first by the square of the second, minus the cube of the second term. In other words: (a-b)^3=a^3-3a^2b+3ab^2-b^3 = (4x)^3+3(4x)^2(-3)+3(4x)(-3)^2+(-3)^3 =. Multiply 3 times -3. Multiply 3 times 4. Calculate the power {\left(-3\right)}^2.

Final Answer

$64x^3-9\cdot 16x^2+108x-27$

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Product of Binomials with Common TermFOIL MethodFactorFind the derivativeFind the integral

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Function Plot

Plotting: $64x^3-144x^2+108x-27$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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