$-9+-2+-4\cdot6$
$\lim_{x\to\infty}\left(1+\frac{37}{x}\right)^{2x}$
$3a+5a$
$\frac{x-3}{x^2-9}=\frac{x+6}{x+3}$
$\left(3x^{3}y^{2}+2xy-5\right)\left(x^{2}y^{3}\right)$
$loga\:c\:=\:b\:$
$-4\:\left(2-3-1\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!