$\left(27:9\right)^4$
$\int1+\tan\left(x\right)^2dx$
$4x+2=-8x+26$
$x\frac{\partial\:\:u}{\partial\:\:x}=y\frac{\partial\:\:u}{\partial\:\:y}$
$y=\frac{4x^{2}-16}{x-2}$
$3y^2-y=0$
$12a^{-5}b^0$
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