$xy^2=0$
$\left(\left(3-4xy\right)^2\right)$
$-4-1+12+5$
$b-b$
$\int\frac{\left(16-x^2\right)^{\frac{3}{2}}}{x^6}\:\:\:dx$
$4x-4^3$
$\int_1^k\left(\frac{3}{2}x\right)dx$
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