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Step-by-step Solution

Solve the inequality $4\left(x-1\right)^2\geq \left(2x-3\right)^2-7$

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Solution

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Answer

$x\geq -0.5$

Step-by-step explanation

Problem to solve:

$4\left(x-1\right)^2\geq \left(2x-3\right)^2-7$
1

Grouping terms

$4\left(x-1\right)^2-\left(2x-3\right)^2\geq -7$

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Answer

$x\geq -0.5$

More problems solved

$\left(a^2+\left(a+x\right)^2\right)\cdot\left(\left(a+x\right)^2+\left(a+2\right)^2\right)$
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$4x-2\left(x-3\right)<0$
$12-\left[x-\left(3-2x\right)+1\right]>2x-1$
$5\left(x+3\right)<\:2x+38$
$4\left(x-1\right)^2\geq \left(2x-3\right)^2-7$

Main topic:

Inequalities

Time to solve it:

~ 0.05 seconds

Related topics:

InequalitiesBinomial theoremSpecial productsPolynomials

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