The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$
$\ln\left(\frac{\left(x+1\right)^2}{x}\right)$
Final Answer
$\ln\left(\frac{\left(x+1\right)^2}{x}\right)$
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