$\frac{5a^5b^{-8}c^4}{a^3}$
$\left(4b+1\right)\left(4b+9\right)$
$-4\:-5+5-\:\left(-12\right)$
$\frac{x^4-3x^2+2}{x+3}$
$\frac{\pi}{3}\int0\:tan6\left(x\right)sec6\left(x\right)dx$
$2e^{\infty^2}$
$x^2=108-3x$
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