$-5-45-15+445+420$
$\left(2x-3\right)\left(5x-2\right)$
$\lim_{x\to\infty}\frac{3x^3+4x^2-5}{2x^2-3x+6}$
$18+4.24$
$a^4x-b^4x-2b^2x$
$1-64p^3$
$o^2+16o+1$
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