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Derive the function (e^(x+y))/(2y-1e^(x+y)) with respect to x

\frac{d}{dx}\left(\frac{e^{\left(x+y\right)}}{2y-1\cdot e^{\left(x+y\right)}}\right)

Step by step solution

Problem

$\frac{d}{dx}\left(\frac{e^{\left(x+y\right)}}{2y-1\cdot e^{\left(x+y\right)}}\right)$

Show full step-by-step solution

Answer

$\frac{e^{\left(y+x\right)}\left(2y-e^{\left(y+x\right)}\right)\frac{d}{dx}\left(y+x\right)-e^{\left(y+x\right)}\cdot\frac{d}{dx}\left(2y-e^{\left(y+x\right)}\right)}{\left(2y-e^{\left(y+x\right)}\right)^2}$

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$\frac{d}{dx}\left(\frac{e^{\left(x+y\right)}}{2y-1\cdot e^{\left(x+y\right)}}\right)$

Main topic:

Differential calculus

Used formulas:

1. See formulas

Time to solve it:

0.29 seconds