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The integral $\int\frac{1}{x^3\sqrt{x^2-9}}dx$ results in: $\frac{1}{27}\left(\frac{1}{2}\mathrm{arcsec}\left(\frac{x}{3}\right)+\frac{3\sqrt{x^2-9}}{2x^2}\right)$
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$\frac{1}{27}\left(\frac{1}{2}\mathrm{arcsec}\left(\frac{x}{3}\right)+\frac{3\sqrt{x^2-9}}{2x^2}\right)$
Learn how to solve integral calculus problems step by step online. Find the integral int(1/(x^3(x^2-9)^1/2))dx+x. The integral \int\frac{1}{x^3\sqrt{x^2-9}}dx results in: \frac{1}{27}\left(\frac{1}{2}\mathrm{arcsec}\left(\frac{x}{3}\right)+\frac{3\sqrt{x^2-9}}{2x^2}\right). Gather the results of all integrals. As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration C. Expand and simplify.