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Step-by-step Solution

Integral of $\frac{v}{v^2-2v+1}$ with respect to x

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Answer

$\frac{xv}{\left(v-1\right)^{2}}+C_0$

Step-by-step explanation

Problem to solve:

$\int\frac{v}{v^2-2v+1}dx$
1

The integral of a constant is equal to the constant times the integral's variable

$x\frac{v}{v^2-2v+1}$
2

Multiplying the fraction and term

$\frac{xv}{v^2-2v+1}$

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Answer

$\frac{xv}{\left(v-1\right)^{2}}+C_0$