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\int\frac{-48x}{\left(x^2-16\right)^2}dx

Integral of (-48x)/((x^2-16)^2)

Answer

$-\frac{3}{4}\int\frac{\cos\left(\theta\right)^{3}\cdot\frac{d}{d\theta}\left(4\sec\left(\theta\right)\right)}{\sin\left(\theta\right)^{4}}d\theta$

Step-by-step explanation

Problem

$\int\frac{-48x}{\left(x^2-16\right)^2}dx$
1

Taking the constant out of the integral

$-48\int\frac{x}{\left(x^2-16\right)^2}dx$

Unlock this step-by-step solution!

Answer

$-\frac{3}{4}\int\frac{\cos\left(\theta\right)^{3}\cdot\frac{d}{d\theta}\left(4\sec\left(\theta\right)\right)}{\sin\left(\theta\right)^{4}}d\theta$

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